-m^2-4m-4=0

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Solution for -m^2-4m-4=0 equation: 



-m^2-4m-4=0

We add all the numbers together, and all the variables

-1m^2-4m-4=0

a = -1; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{4}{-2}=-2$

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